Comments on: Checking if a number is fibonacci

By: ss

ss — Fri, 11 Nov 2022 09:11:52 +0000

yes

By: gaurav

gaurav — Mon, 27 Dec 2021 07:12:41 +0000

smoothly explained.

By: gaurav

gaurav — Mon, 27 Dec 2021 07:10:40 +0000

In reply to vishal.

int Fibonacci(int a)
{
if (a==0) return 0;
else if(a==1)
return 1;
else
return ( Fibonacci(a-1)+ Fibonacci(a-2));
}
visit: https://studyfame.com/c-program/fibonacci-series-program-in-c-using-recursion

By: vishal

vishal — Mon, 27 Dec 2021 07:06:11 +0000

how can I do this with recursion

By: Havillaj

Havillaj — Sat, 06 Nov 2021 20:08:41 +0000

In reply to Shaan007. What are the names of your files

By: ur mum

ur mum — Mon, 11 Oct 2021 09:55:23 +0000

In reply to Nguyễn Thanh Trọng. No u!

By: Sunil Chaudhari

Sunil Chaudhari — Thu, 24 Sep 2020 13:43:30 +0000

In reply to muhammad. Change the condition for the while loop Replace < by <= It will give correct output.

By: Shaan007

Shaan007 — Sun, 20 Sep 2020 14:49:22 +0000

This will 100% work. And it’s compact as well…
#include
#include
#include
int main()
{
int n,calc1,calc2,pwr;
printf(“Enter a number : “);
scanf(“%d”,&n);
pwr= pow(n,2)+0.5;
calc1=(5*pwr)+4;
calc2=(5*pwr)-4;
if(sqrt(calc1)==round(sqrt(calc1)) || sqrt(calc2)==round(sqrt(calc2)))
{
printf(“The number is Fibonacci”);
}
else
{
printf(“The number is not Fibonacci”);
}
getch();
return(0);
}

By: Nguyễn Thanh Trọng

Nguyễn Thanh Trọng — Wed, 24 Jun 2020 08:26:22 +0000

In reply to Yash. you are stupid! you can use function pow (n,2) in include

By: Yash

Yash — Tue, 21 Apr 2020 10:11:08 +0000

In reply to muhammad. Maybe you are calculating 5*n^2+4 in the code, but in c,c++ it should be 5*n*n-4.